interpolateTemperature

Interpolate temperature in a thermal result at arbitrary spatial locations

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Syntax

Tintrp = interpolateTemperature(thermalresults,xq,yq)
Tintrp = interpolateTemperature(thermalresults,xq,yq,zq)
Tintrp = interpolateTemperature(thermalresults,querypoints)
Tintrp = interpolateTemperature(___,iT)

Description

example

Tintrp = interpolateTemperature(thermalresults,xq,yq) returns the interpolated temperature values at the 2-D points specified in xq and yq. This syntax is valid for both the steady-state and transient thermal models.

example

Tintrp = interpolateTemperature(thermalresults,xq,yq,zq) returns the interpolated temperature values at the 3-D points specified in xq, yq, and zq. This syntax is valid for both the steady-state and transient thermal models.

example

Tintrp = interpolateTemperature(thermalresults,querypoints) returns the interpolated temperature values at the points in querypoints. This syntax is valid for both the steady-state and transient thermal models.

example

Tintrp = interpolateTemperature(___,iT) returns the interpolated temperature values for the transient thermal model at times iT.

Examples

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Open Live Script

Create a thermal model for steady-state analysis. 

thermalmodel = createpde('thermal');

Create the geometry and include it in the model.

R1 = [3,4,-1,1,1,-1,1,1,-1,-1]';
g = decsg(R1, 'R1', ('R1')');
geometryFromEdges(thermalmodel,g);
pdegplot(thermalmodel,'EdgeLabels','on')
xlim([-1.5,1.5])
axis equal

Assuming that this is an iron plate, assign a thermal conductivity of 79.5 W/(m*K). Because this is a steady-state model, you do not need to assign mass density or specific heat values.

thermalProperties(thermalmodel,'ThermalConductivity',79.5,'Face',1);

Apply a constant temperature of 300 K to the bottom of the plate (edge 3). Also, assume that the top of the plate (edge 1) is insulated, and apply convection on the two sides of the plate (edges 2 and 4).

thermalBC(thermalmodel,'Edge',3,'Temperature',300);
thermalBC(thermalmodel,'Edge',1,'HeatFlux',0);
thermalBC(thermalmodel,'Edge',[2,4],...
                       'ConvectionCoefficient',25,...
                       'AmbientTemperature',50);

Mesh the geometry and solve the problem.

generateMesh(thermalmodel);
results = solve(thermalmodel)
results = 
  SteadyStateThermalResults with properties:

    Temperature: [1541x1 double]
     XGradients: [1541x1 double]
     YGradients: [1541x1 double]
     ZGradients: []
           Mesh: [1x1 FEMesh]

The solver finds the values of temperatures and temperature gradients at the nodal locations. To access these values, use results.Temperature, results.XGradients, and so on. For example, plot the temperatures at nodal locations.

figure;
pdeplot(thermalmodel,'XYData',results.Temperature,...
                     'Contour','on','ColorMap','hot');

Interpolate the resulting temperatures to a grid covering the central portion of the geometry, for x and y from -0.5 to 0.5.

v = linspace(-0.5,0.5,11);
[X,Y] = meshgrid(v);

Tintrp = interpolateTemperature(results,X,Y);

Reshape the Tintrp vector and plot the resulting temperatures.

Tintrp = reshape(Tintrp,size(X));

figure
contourf(X,Y,Tintrp)
colormap(hot)
colorbar

Alternatively, you can specify the grid by using a matrix of query points.

querypoints = [X(:),Y(:)]';
Tintrp = interpolateTemperature(results,querypoints);
Open Live Script

Create a thermal model for steady-state analysis.

thermalmodel = createpde('thermal');

Create the following 3-D geometry and include it in the model.

importGeometry(thermalmodel,'Block.stl'); 
pdegplot(thermalmodel,'FaceLabels','on','FaceAlpha',0.5)
title('Copper block, cm')
axis equal

Assuming that this is a copper block, the thermal conductivity of the block is approximately 4 W/(cm*K).

thermalProperties(thermalmodel,'ThermalConductivity',4);

Apply a constant temperature of 373 K to the left side of the block (edge 1) and a constant temperature of 573 K at the right side of the block.

thermalBC(thermalmodel,'Face',1,'Temperature',373);
thermalBC(thermalmodel,'Face',3,'Temperature',573);

Apply a heat flux boundary condition to the bottom of the block.

thermalBC(thermalmodel,'Face',4,'HeatFlux',-20);

Mesh the geometry and solve the problem.

generateMesh(thermalmodel);
thermalresults = solve(thermalmodel)
thermalresults = 
  SteadyStateThermalResults with properties:

    Temperature: [12691x1 double]
     XGradients: [12691x1 double]
     YGradients: [12691x1 double]
     ZGradients: [12691x1 double]
           Mesh: [1x1 FEMesh]

The solver finds the values of temperatures and temperature gradients at the nodal locations. To access these values, use results.Temperature, results.XGradients, and so on. For example, plot temperatures at nodal locations.

figure;
pdeplot3D(thermalmodel,'ColorMapData',thermalresults.Temperature)

Create a grid specified by x, y, and z coordinates and interpolate temperatures to the grid.

[X,Y,Z] = meshgrid(1:16:100,1:6:20,1:7:50);

Tintrp = interpolateTemperature(thermalresults,X,Y,Z);

Create a contour slice plot for fixed values of the y coordinate.

figure

Tintrp = reshape(Tintrp,size(X));

contourslice(X,Y,Z,Tintrp,[],1:6:20,[])
xlabel('x')
ylabel('y')
zlabel('z')
xlim([1,100])
ylim([1,20])
zlim([1,50])
axis equal
view(-50,22)
colorbar

Alternatively, you can specify the grid by using a matrix of query points.

querypoints = [X(:),Y(:),Z(:)]';
Tintrp = interpolateTemperature(thermalresults,querypoints);

Create a contour slice plot for four fixed values of the z coordinate.

figure

Tintrp = reshape(Tintrp,size(X));

contourslice(X,Y,Z,Tintrp,[],[],1:7:50)
xlabel('x')
ylabel('y')
zlabel('z')
xlim([1,100])
ylim([1,20])
zlim([1,50])
axis equal
view(-50,22)
colorbar

Open Live Script

Solve a 2-D transient heat transfer problem on a square domain and compute temperatures at the convective boundary.

Create a transient thermal model for this problem.

thermalmodel = createpde('thermal','transient');

Create the geometry and include it in the model.

g = @squareg;
geometryFromEdges(thermalmodel,g);
pdegplot(thermalmodel,'EdgeLabels','on')
xlim([-1.2,1.2])
ylim([-1.2,1.2])
axis equal

Assign the following thermal properties:

  • Thermal conductivity is 100 W/(m*C)

  • Mass density is 7800 kg/m^3

  • Specific heat is 500 J/(kg*C)

thermalProperties(thermalmodel,'ThermalConductivity',100,...
                               'MassDensity',7800,...
                               'SpecificHeat',500);

Apply insulated boundary conditions on three edges and the free convection boundary condition on the right edge.

thermalBC(thermalmodel,'Edge',[1,3,4],'HeatFlux',0);
thermalBC(thermalmodel,'Edge',2,...
                       'ConvectionCoefficient',5000,...
                       'AmbientTemperature',25);

Set the initial conditions: uniform room temperature across domain and higher temperature on the left edge.

thermalIC(thermalmodel,25);
thermalIC(thermalmodel,100,'Edge',4);

Generate a mesh and solve the problem using 0:1000:200000 as a vector of times.

generateMesh(thermalmodel);
tlist = 0:1000:200000;
thermalresults = solve(thermalmodel,tlist)
thermalresults = 
  TransientThermalResults with properties:

      Temperature: [1541x201 double]
    SolutionTimes: [1x201 double]
       XGradients: [1541x201 double]
       YGradients: [1541x201 double]
       ZGradients: []
             Mesh: [1x1 FEMesh]

Define a line at convection boundary and compute temperature gradients across that line.

X = -1:0.1:1;
Y = ones(size(X));

Tintrp = interpolateTemperature(thermalresults,X,Y,1:length(tlist));

Plot the interpolated temperature Tintrp along the x axis for the following values from the time interval tlist.

figure
t = [51:50:201];
for i = t
  p(i) = plot(X,Tintrp(:,i),'DisplayName', strcat('t=', num2str(tlist(i))));
  hold on
end
legend(p(t))
xlabel('x')
ylabel('Tintrp')

Input Arguments

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Solution of thermal problem, specified as a SteadyStateThermalResults object or a TransientThermalResults object. Create thermalresults using solve.

Example: thermalresults = solve(thermalmodel)

x-coordinate query points, specified as a real array. interpolateTemperature evaluates temperatures at the 2-D coordinate points [xq(i),yq(i)] or at the 3-D coordinate points [xq(i),yq(i),zq(i)]. So xq, yq, and (if present) zq must have the same number of entries.

interpolateTemperature converts query points to column vectors xq(:), yq(:), and (if present) zq(:). It returns temperatures in the form of a column vector of the same size. To ensure that the dimensions of the returned solution is consistent with the dimensions of the original query points, use reshape. For example, use Tintrp = reshape(Tintrp,size(xq)).

Data Types: double

y-coordinate query points, specified as a real array. interpolateTemperature evaluates temperatures at the 2-D coordinate points [xq(i),yq(i)] or at the 3-D coordinate points [xq(i),yq(i),zq(i)]. So xq, yq, and (if present) zq must have the same number of entries. Internally, interpolateTemperature converts query points to the column vector yq(:).

Data Types: double

z-coordinate query points, specified as a real array. interpolateTemperature evaluates temperatures at the 3-D coordinate points [xq(i),yq(i),zq(i)]. So xq, yq, and zq must have the same number of entries. Internally, interpolateTemperature converts query points to the column vector zq(:).

Data Types: double

Query points, specified as a real matrix with either two rows for 2-D geometry, or three rows for 3-D geometry. interpolateTemperature evaluates temperatures at the coordinate points querypoints(:,i), so each column of querypoints contains exactly one 2-D or 3-D query point.

Example: For 2-D geometry, querypoints = [0.5,0.5,0.75,0.75; 1,2,0,0.5]

Data Types: double

Time indices, specified as a vector of positive integers. Each entry in iT specifies a time index.

Example: iT = 1:5:21 specifies every fifth time-step up to 21.

Data Types: double

Output Arguments

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Temperatures at query points, returned as an array. For query points that are outside the geometry, Tintrp = NaN.

See Also

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Topics

Introduced in R2017a

Partial Differential Equation Toolbox Documentation

Support