Create a 3-by-3 identity matrix.

A = eye(3)

A = 3×3

     1     0     0
     0     1     0
     0     0     1

Find the logical negation of A. The new matrix has type logical.

B = ~A

B = 3x3 logical array

   0   1   1
   1   0   1
   1   1   0

Execute code based on a condition using the logical not operator in the context of an if loop.

Create a logical variable A.

A = false;

Use A to write an if/else code block. Wrap the if/else block in a for loop so that it executes four times.

for k = 1:4
    if ~A
        disp('IF block')
        A = true;
    else
        disp('ELSE block')
    end
end

IF block
ELSE block
ELSE block
ELSE block

On the first iteration, A is false, so the if block executes since ~A is true. However, the if block also changes the value of A to true. In the remaining iterations, ~A is false and the else block executes.