Find Antipode of Given Point

Given a point (43ºN, 15ºE), find its antipode:

[newlat,newlong] = antipode(43,15)
newlat =
         -43
newlong =
         -165			

or (43ºS, 165ºW).

Find Antipode of North and South Poles

Perhaps the most obvious antipodal points are the North and South Poles. The function antipode demonstrates this:

[newlat,newlong] = antipode(90,0,'degrees')
newlat =
         -90
newlong =
         180			

Note that in this case longitudes are irrelevant because all meridians converge at the poles.

Find Antipode of MathWorks Headquarters

This example shows how to find the antipode of the location of the MathWorks corporate headquarters in Natick, Massachusetts. The example maps the headquarters location and its antipode in an orthographic projection.

Specify latitude and longitude as degree-minutes-seconds and then convert to decimal degrees.

mwlat = dms2degrees([ 42 18 2.5])

mwlat = 42.3007

mwlon = dms2degrees([-71 21 7.9])

mwlon = -71.3522

Find the antipode.

[amwlat amwlon] = antipode(mwlat,mwlon)

amwlat = -42.3007

amwlon = 108.6478

Prove that these points are antipodes. The distance function shows them to be 180 degrees apart.

dist = distance(mwlat,mwlon,amwlat,amwlon)

dist = 180.0000

Generate a map centered on the original point and then another map centered on the antipode.

figure
subplot(1,2,1)
axesm ('MapProjection','ortho','origin',[mwlat mwlon],...
       'frame','on','grid','on')
load coastlines
geoshow(coastlat,coastlon,'displaytype','polygon')
geoshow(mwlat,mwlon,'Marker','o','Color','red')
title(sprintf('Looking down at\n(%s,%s)', ...
    angl2str(mwlat,'ns'), angl2str(mwlon,'ew')))

subplot(1,2,2)
axesm ('MapProjection','ortho','origin',[amwlat amwlon],...
       'frame','on','grid','on')
geoshow(coastlat,coastlon,'displaytype','polygon')
geoshow(amwlat,amwlon,'Marker','o','Color','red')
title(sprintf('Looking down at\n(%s,%s)', ...
    angl2str(amwlat,'ns'), angl2str(amwlon,'ew')))