%% SFDR of Sinusoid
% Obtain the SFDR for a 10 MHz tone with amplitude 1 sampled at 100 MHz. There is a spur at the 1st harmonic (20 MHz) with an amplitude of 3.16\times10^{-4}.

deltat = 1e-8;
fs = 1/deltat;
t = 0:deltat:1e-5-deltat;
x = cos(2*pi*10e6*t)+3.16e-4*cos(2*pi*20e6*t);
r = sfdr(x,fs)

%
% Display the spectrum of the signal. Annotate the fundamental, the DC value, the spur, and the SFDR.

sfdr(x,fs);

% Copyright 2015 The MathWorks, Inc.